{"id":2132,"date":"2023-11-24T23:30:00","date_gmt":"2023-11-25T04:30:00","guid":{"rendered":"http:\/\/underthehood.blogwyrm.com\/?p=2132"},"modified":"2023-11-18T19:56:31","modified_gmt":"2023-11-19T00:56:31","slug":"on-an-operator-relation","status":"publish","type":"post","link":"https:\/\/underthehood.blogwyrm.com\/?p=2132","title":{"rendered":"On an Operator Relation"},"content":{"rendered":"\n<p>There is a surprisingly frequent need to compute the quantity $O = 1 + G$ where both $O$ and $G$ are operators. These operators can be algebraic, often in the form of a matrix, or a derivative operator, and can be either finite- or infinite-dimensional. One typical example consists of constructing the local representation of a Lie group operator &#8216;near&#8217; the identity &#8211; a construction that shows up most everywhere in quantum mechanics and in general relativity.<\/p>\n\n\n\n<p>The interesting next step is to determine what is the inverse operator $O^{-1}$ in terms of $G$ such that<\/p>\n\n\n\n\\[ O^{-1} O = 1 \\; , \\]\n\n\n\n<p>which translates to<\/p>\n\n\n\n\\[ (1+G)^{-1} (1+G) = 1 \\; .\\]\n\n\n\n<p>To proceed, we can `decorated&#8217; the right hand side with a infinite string of suggestive zeros<\/p>\n\n\n\n\\[ (1+G)^{-1} (1 + G) = 1 + (G &#8211; G) + (G^2 &#8211; G^2) + \\cdots \\; .\\]\n\n\n\n<p>Next we indulge in some inspired rearrangement of terms to get<\/p>\n\n\n\n\\[ (1+G)^{-1} (1 + G) = \\left[ (1 + G) &#8211; (G + G^2) + (G^2 + G^3) &#8211; (G^3 + G^4) \\cdots \\right] \\; . \\]\n\n\n\n<p>We can now factor $(1+G)$ out to the right to get<\/p>\n\n\n\n\\[ (1+G)^{-1} (1+G) = \\left[ 1 &#8211; G + G^2 &#8211; G^3 + \\cdots \\right] (1 + G) \\; .\\]\n\n\n\n<p>Comparing the two sides we conclude that the quantity in the brackets must then be a series representation of the inverse<\/p>\n\n\n\n\\[ (1+G)^{-1} = 1 &#8211; G + G^2 &#8211; G^3 + \\cdots \\; .\\]\n\n\n\n<p>If the construction is correct, then the expansion must also serve as a right inverse. That is to say,<\/p>\n\n\n\n\\[ (1 + G) (1 + G)^{-1} = 1 \\; .\\]\n\n\n\n<p>Substituting the form determined above yields<\/p>\n\n\n\n\\[ (1 + G) (1 &#8211; G + G^2 &#8211; G^3 + \\cdots) = 1 + G &#8211; G &#8211; G^2 + G^2 + G^3 &#8211; G^3 &#8211; G^4 + \\cdots \\; . \\]\n\n\n\n<p>It is interesting to note that this operator series is formally similar the Taylor series expansion for the geometric series:<\/p>\n\n\n\n\\[ \\frac{1}{1+x} = 1 &#8211; x + x^2 &#8211; x^3 + \\cdots \\; .\\]\n\n\n\n<p>Both series have limited domains of applicability. For the scalar function just expanded, it is well-known that the condition on $x$ for the expansion to be within the radius of convergence is $|x| &lt; 1$, this latter the condition being the domain of applicability.<\/p>\n\n\n\n<p>For the operator version, the corresponding condition isn&#8217;t nearly as clear and that will be the subject of next month&#8217;s blog.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>There is a surprisingly frequent need to compute the quantity $O = 1 + G$ where both $O$ and $G$ are operators. These operators can be algebraic, often in the&#8230; <a class=\"read-more-button\" href=\"https:\/\/underthehood.blogwyrm.com\/?p=2132\">Read more &gt;<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-2132","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"_links":{"self":[{"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=\/wp\/v2\/posts\/2132","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=2132"}],"version-history":[{"count":5,"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=\/wp\/v2\/posts\/2132\/revisions"}],"predecessor-version":[{"id":2137,"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=\/wp\/v2\/posts\/2132\/revisions\/2137"}],"wp:attachment":[{"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=2132"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=2132"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/underthehood.blogwyrm.com\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=2132"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}